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AIIMS 2011

Exam: AIIMS
Year: 2011
Subject: Chemistry
Chapter: Chemical Bonding and Molecular Structure

AIIMS 2011 · Chemistry · Chemical Bonding and Molecular Structure

Decreasing order of bond angle is

Decreasing order of bond angle is

Options

A $\mathrm{BeCl}_2>\mathrm{NO}_2>\mathrm{SO}_2$
B $\mathrm{BeCl}_2>\mathrm{SO}_2>\mathrm{NO}_2$
C $\mathrm{SO}_2>\mathrm{BeCl}_2>\mathrm{NO}_2$
D $\mathrm{SO}_2>\mathrm{NO}_2>\mathrm{BeCl}_2$

Correct answer

A. $\mathrm{BeCl}_2>\mathrm{NO}_2>\mathrm{SO}_2$

Step-by-step solution

Compound:

\mathrm{BeCl}_2>\mathrm{NO}_2>\mathrm{SO}_2

Angle :

180^{\circ}>132^{\circ}>119.5^{\circ}

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