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JEE Main 20257 AprilMorning Shift
Exam
JEE Main
Year
2025
Date
7 April
Shift
Morning Shift
Subject
Physics
Chapter
Rotational Motion

JEE Main 2025 · 7 April · Morning Shift · Physics · Rotational Motion

A, B and C are disc, solid sphere and spherical shell respectively...

A,B\mathrm{A}, \mathrm{B} and C are disc, solid sphere and spherical shell respectively with same radii and masses. These masses are placed as shown in figure.
A, B and C are disc, solid sphere and spherical shell respectively with same radii and masses. These masses are placed
The moment of inertia of the given system about PQP Q is X15I\frac{X}{15} I, where II is the moment of inertia of the disc about its diameter. The value of x is _______.

Correct answer

0

Step-by-step solution

A, B and C are disc, solid sphere and spherical shell respectively with same radii and masses. These masses are placed
All bodies have same mass and same radius.
A→\mathrm{A} \rightarrow Disc
B→\mathrm{B} \rightarrow Solid sphere
C→\mathrm{C} \rightarrow Spherical shell
and, I=MR24\mathrm{I}=\frac{\mathrm{MR}^2}{4}
IPQ=MR24+(25MR2+MR2)+(23MR2+MR2)\mathrm{I}_{\mathrm{PQ}}=\frac{\mathrm{MR}^2}{4}+\left(\frac{2}{5} \mathrm{MR}^2+\mathrm{MR}^2\right)+\left(\frac{2}{3} \mathrm{MR}^2+\mathrm{MR}^2\right)
IPQ=15MR2+24MR2+60MR2+40MR2+60MR260\mathrm{I}_{\mathrm{PQ}}=\frac{15 \mathrm{MR}^2+24 \mathrm{MR}^2+60 \mathrm{MR}^2+40 \mathrm{MR}^2+60 \mathrm{MR}^2}{60}
IPQ=19960MR2=19915(MR24)\mathrm{I}_{\mathrm{PQ}}=\frac{199}{60} \mathrm{MR}^2=\frac{199}{15}\left(\frac{\mathrm{MR}^2}{4}\right)
=19915I=\frac{199}{15} \mathrm{I}
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