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JEE Main 20254 AprilEvening Shift
Exam
JEE Main
Year
2025
Date
4 April
Shift
Evening Shift
Subject
Physics
Chapter
Rotational Motion

JEE Main 2025 · 4 April · Evening Shift · Physics · Rotational Motion

A solid sphere with uniform density and radius R is rotating...

A solid sphere with uniform density and radius R is rotating initially with constant angular velocity (ω1)\left(\omega_1\right) about its diameter. After some time during the rotation its starts loosing mass at a uniform rate, with no change in its shape. The angular velocity of the sphere when its radius become R/2R / 2 is xω1x \omega_1. The value of xx is ________

Correct answer

0

Step-by-step solution

When sphere is of radius RR, its mass is MM, when radius is reduced to R2\frac{\mathrm{R}}{2}, mass will reduced to M8\frac{\mathrm{M}}{8} Now by conservation of angular momentum
<br/>(τext=0)L1=L2I1ω1=I2ω2(25MR2)ω1=(25(M8)(R2)2)ω2<br/>\begin{aligned}<br/>& \left(\tau_{e x t}=0\right) \\ & L_1=L_2 \\ & I_1 \omega_1=I_2 \omega_2 \\ & \left(\frac{2}{5} M R^2\right) \omega_1=\left(\frac{2}{5}\left(\frac{\mathrm{M}}{8}\right)\left(\frac{\mathrm{R}}{2}\right)^2\right) \omega_2<br/>\end{aligned}
ω2=32ω1\omega_2=32 \omega_1 value of x is 32
Answer is 32
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