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JEE Main 20254 AprilEvening Shift
Exam
JEE Main
Year
2025
Date
4 April
Shift
Evening Shift
Subject
Physics
Chapter
Rotational Motion

JEE Main 2025 · 4 April · Evening Shift · Physics · Rotational Motion

A wheel is rolling on a plane surface. The speed of a particle on...

A wheel is rolling on a plane surface. The speed of a particle on the highest point of the rim is 8 m/s8 \mathrm{~m} / \mathrm{s}. The speed of the particle on the rim of the wheel at the same level as the centre of wheel, will be :A wheel is rolling on a plane surface. The speed of a particle on the highest point of the rim is 8 ~m / s . The speed

Options

  1. A42 m/s4 \sqrt{2} \mathrm{~m} / \mathrm{s}
  2. B8 m/s8 \mathrm{~m} / \mathrm{s}
  3. C4 m/s4 \mathrm{~m} / \mathrm{s}
  4. D82 m/s8 \sqrt{2} \mathrm{~m} / \mathrm{s}

Correct answer

A. 42 m/s4 \sqrt{2} \mathrm{~m} / \mathrm{s}

Step-by-step solution

A wheel is rolling on a plane surface. The speed of a particle on the highest point of the rim is 8 ~m / s . The speed
If VB=2VV_B=2 V
Point A is instantaneous center of rotation
Given VB=8 m/sV_B=8 \mathrm{~m} / \mathrm{s}
<br/>V=4 m/s Vp=2v⇒ Vp=42 m/scorrect⁡(1)<br/>\begin{aligned}<br/>& \mathrm{V}=4 \mathrm{~m} / \mathrm{s} \\ & \mathrm{~V}_{\mathrm{p}}=\sqrt{2} \mathrm{v} \Rightarrow \mathrm{~V}_{\mathrm{p}}=4 \sqrt{2} \mathrm{~m} / \mathrm{s} \\ & \operatorname{correct}(1)<br/>\end{aligned}
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