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JEE Main202524 Jan 2025Morning ShiftPhysicsRotational MotionActual

An object of mass ' m ' is projected from origin in a vertical x y plane at an angle 45^ with the x axis with an initial velocity v ₀ . The magnitude and direction of the angular momentum of the object with respect to origin, when it reaches at the maximum height, will be [ g is acceleration due to gravity]

Options

  1. Am v_o^3 2 2 g along negative z -axis
  2. Bm v_o^3 4 2 g along positive z -axis
  3. Cm v_o^3 4 2 g along negative z -axis
  4. Dm v_o^3 2 2 g along positive z -axis

Correct answer

C. m v_o^3 4 2 g along negative z -axis

Step-by-step solution

aligned & H = ( v ₀ 2 )^2 2 ~g = v ₀^2 4 ~g & ~L = mvh & ~L = m v ₀ 2 v ₀^2 4 ~g aligned

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