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JEE Main202431 Jan 2024Evening ShiftPhysicsRotational MotionActual

Two identical spheres each of mass 2 kg and radius 50 cm are fixed at the ends of a light rod so that the separation between the centers is 150 cm . Then, moment of inertia of the system about an axis perpendicular to the rod and passing through its middle point is x 20 kg m 2 , where the value of x is

Correct answer

0

Step-by-step solution

Using parallel axis theorem, we can write total moment of inertia as, I = 2 5 m R 2 + m d 2 × 2 ⇒ I = 2 2 5 × 2 × 1 2 2 + 2 × 3 4 2 = 53 20 kg m 2 Therefore, x = 53 .

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