A body of mass m is projected with a speed u making an angle of 45 o with the ground. The angular momentum of the body about the point of projection, at the highest point is expressed as 2 m u 3 X g . The value of X is_______.

Step-by-step solution

Consider projection as shown in above diagram. At the topmost point, velocity of the body will be u cos 45 ° . Therefore, we can write the required angular momentum as L = m u H × H = m u cos θ u 2 sin 2 θ 2 g = m u 3 × 1 4 2 g ⇒ X = 8