The position vector of 1   kg object is r → = 3 i ^ - j ^   m and its velocity v → = 3 j ^ + k ^   m   s - 1 . The magnitude of its angular momentum is x   N   m   s , where x is

Step-by-step solution

Angular momentum of a particle is given by, L → = r → × P → = r → × m v → also m = 1   kg . ⇒ L → = 3 i ^ - j ^ × 3 j ^ + k ^ = 9 k ^ - 3 j ^ - i ^   N   m   s The magnitude of the angular momentum will be, ⇒ L → = 9 2 + 3 2 + 1 2 = 91   N   m   s Therefore, the value of x = 91 .