The position vector of 1kg object is → r = (3 ^ i - ^ j )m and its...

Angular momentum of a particle is given by,

$\overset{\to}{L} = \overset{\to}{r} \times \overset{\to}{P} = \overset{\to}{r} \times m\overset{\to}{v}$ also $m = 1kg$.

⇒ \overset{\to}{L} = \left(3\overset{^}{i} - \overset{^}{j}\right) \times \left(3\overset{^}{j} + \overset{^}{k}\right) = \left(9\overset{^}{k} - 3\overset{^}{j} - \overset{^}{i}\right)Nms

The magnitude of the angular momentum will be,

$⇒ \left|\overset{\to}{L}\right| = \sqrt{{9}^{2} + {3}^{2} + {1}^{2}} = \sqrt{91}Nms$

Therefore, the value of $x = 91$.