Water falls from a height of 200 m into a pool. Calculate the rise in temperature of the water assuming no heat dissipation from the water in the pool.
$\left(\right.$ Take $g=10 \mathrm{~m} / \mathrm{s}^2, specific heat$ of water $\left.=4200 \mathrm{~J} /(\mathrm{kg} \mathrm{K})\right)$

Question

Water falls from a height of 200 m into a pool. Calculate the rise in temperature of the water assuming no heat dissipation from the water in the pool.

\left(\right.

Take

g=10 \mathrm{~m} / \mathrm{s}^2, specific heat

of water

\left.=4200 \mathrm{~J} /(\mathrm{kg} \mathrm{K})\right)

Quantrex Academy · Accepted Answer

Correct answer: D. 0.48 K

aligned & mgh=ms Δ T & Δ T= gh s =(10 × 200)/(4200) ~K=(10)/(21) ~K aligned

Water falls from a height of 200 m into a pool. Calculate the rise...

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