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JEE Main 202224 JuneEvening Shift
Exam
JEE Main
Year
2022
Date
24 June
Shift
Evening Shift
Subject
Physics
Chapter
Thermal Properties of Matter

JEE Main 2022 · 24 June · Evening Shift · Physics · Thermal Properties of Matter

A 100g of iron nail is hit by a 1 . 5kg hammer striking at a...

A 100g100g of iron nail is hit by a 1.5kg1 . 5kg hammer striking at a velocity of 60ms−160{ms}^{- 1}. What will be the rise in the temperature of the nail if one fourth of energy of the hammer goes into heating the nail ? [Specific heat capacity of iron =0.42Jg−1C∘−1= 0 . 42{Jg}^{- 1}{C ∘}^{- 1}]

Options

  1. A16.07°C16 . 07 ° C
  2. B6.75°C6 . 75 ° C
  3. C1600°C1600 ° C
  4. D675°C675 ° C

Correct answer

A. 16.07°C16 . 07 ° C

Step-by-step solution

If we heat-up an object, then, the energy is used to either change the temperature of the body or to change the state of the body.
If it changes the temperature, then,

Q=mS∆TQ = mS ∆ T
where, QQ is the heat given, mm is the mass and ∆T∆ T is the change in temperature.

We know that a moving object has an energy in the form of kinetic energy, i.e.,
KE=12mv2KE = \dfrac{1}{2}m{v}^{2}

When that moving object strikes another object, it loses some energy which changes into the heat energy and this heat energy increases the temperature of the object.
Given a hammer of 1.5kg1 . 5kg is moving with 60ms−160m{s}^{- 1}.
Kinetic energy =12mv2=12(1.5)(60)2=2700J= \dfrac{1}{2}m{v}^{2} = \dfrac{1}{2} ( 1 . 5 ) ( 60{)}^{2} = 2700J
One-fourth of kinetic energy changes into heat energy.
⇒14(KE)=⇒ \dfrac{1}{4} ( KE ) = Heat energy
⇒14(KE)=m(S)(∆T)⇒ \dfrac{1}{4} ( KE ) = m ( S ) ( ∆ T )
⇒14(2700)=(100)(0.42)(∆T)⇒ \dfrac{1}{4} ( 2700 ) = ( 100 ) ( 0 . 42 ) ( ∆ T )
⇒∆T=16.07°C⇒ ∆ T = 16 . 07 ° C

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