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JEE Main2012PhysicsThermal Properties of MatterActual

A liquid in a beaker has temperature (t) at time t and ₀ is temperature of surroundings, then according to Newton's law of cooling the correct graph between _e ( - ₀ ) and t is

Correct answer

0

Step-by-step solution

According to Newtons law of cooling. d dt - ( - ₀ ) d dt =- k ( - ₀ ) d - ₀ = -k d t ( - ₀ )=-k t+c Hence the plot of ( - ₀ ) vs t should be a straight line with negative slope.

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