JEE Main20249 Apr 2024Morning ShiftPhysicsThermodynamicsActual
A sample of 1 mole gas at temperature T is adiabatically expanded to double its volume. If adiabatic constant for the gas is = 3 2 , then the work done by the gas in the process is:
Options
- AR T [2- 2 ]
- BT R [2+ 2 ]
- CRT [2- 2 ]
- DRT [2+ 2 ]
Correct answer
C. RT [2- 2 ]
Step-by-step solution
aligned & TV ^ -1 = constant & T ( V )^ 3 2 -1 = T _ f (2 ~V )^ 3 2 -1 & TV ^ 1 2 = T _ f (2)^ 1 2 ( ~V )^ 1 2 & T _ f = ( T 2 ) & Now, W.D. = nR T 1- = 1 R [ T 2 - T ] 1- 3 2 & W.D. =2 RT [1- 1 2 ] & W.D. = RT [2- 2 ] aligned