JEE Main20236 Apr 2023Morning ShiftPhysicsThermodynamicsActual
A source supplies heat to a system at the rate of 1000 W . If the system performs work at a rate of 200 W . The rate at which internal energy of the system increases is
Options
- A600   W
- B800   W
- C500   W
- D1200   W
Correct answer
B. 800   W
Step-by-step solution
According to the first law of thermodynamics, Q = W + U . Upon differentiation, we get d Q d t = d W d t + d U d t ⇒ d U d t = d Q d t - d W d t Given: d Q d t = 1000   W d W d t = 200   W Therefore, d U d t = 1000   W - 200   W = 800   W