For three low density gases A , B , C pressure versus temperature graphs are plotted while keeping them at constant volume, as shown in the figure The temperature corresponding to the point ' K ' is:

Step-by-step solution

In case of constant volume process, i.e., isochoric process, From ideal gas equation, P T = n R V = constant Or we have, P = n R V t + 273 If P = 0 ⇒ t = - 273 ° C Thus, when temperature goes to - 273 ° C , all constituent particles get freezed and pressure goes to zero irrespective of the density of gas. Hence, the temperature corresponding to the point K = - 273 ° C .