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A certain amount of gas of volume V at 27 ° C temperature and pressure 2 × 10 7 N m - 2 expands isothermally until its volume gets doubled. Later it expands adiabatically until its volume gets redoubled. The final pressure of the gas will be (Use γ = 1 . 5 )

Options

  1. A3 . 536 × 10 5   Pa
  2. B3 . 536 × 10 6   Pa
  3. C1 . 25 × 10 6   Pa
  4. D1 . 25 × 10 5   Pa

Correct answer

B. 3 . 536 × 10 6   Pa

Step-by-step solution

Given here, P 1 = 2 × 10 7   N   m - 2 = 2 × 10 7   Pa Using Boyle's law, P 1 V 1 = P 2 V 2 Since V 2 = 2 V 1 . Hence, P 2 = P 1 2 (isothermal expansion) P 2 = 1 × 10 7   Pa Now, during adiabatic expansion, P 2 V 2 γ = P 3 2 V 2 γ P 3 = 1 × 10 7 2 1 . 5 = 3 . 536 × 10 6   Pa

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