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JEE Main202229 Jun 2022Evening ShiftPhysicsThermodynamicsActual

Starting with the same initial conditions, an ideal gas expands from volume V 1 to V 2 in three different ways. The work done by the gas is W 1 if the process is purely isothermal, W 2 , if the process is purely adiabatic and W 3 if the process is purely isobaric. Then, choose the correct option

Options

  1. AW 2 < W 1 < W 3
  2. BW 1 < W 2 < W 3
  3. CW 2 < W 3 < W 1
  4. DW 3 < W 1 < W 2

Correct answer

A. W 2 < W 1 < W 3

Step-by-step solution

As we know, in isobaric process pressure remains constant and magnitude of slope of adiabatic curve will be more than the isothermal curve at the common point, therefore diagram for process will be as given below. Also, W = area under P - V curve. Hence, ∴   W 2 < W 1 < W 3

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