300calories of heat is given to a heat engine, and it rejects 225calories of heat. If source temperature is 227 ° C , then the temperature of sink will be _____ C ∘ .

Question

Quantrex Academy · Accepted Answer

Correct answer: 0

300calories of heat is given to a heat engine, and it rejects 225calories of heat. If source temperature is 227 ° C ,

Efficiency of Carnot engine is given by $η = 1 - \dfrac{{Q}_{2}}{{Q}_{1}} = 1 - \dfrac{{T}_{2}}{{T}_{1}}$ .

$⇒ 1 - \dfrac{225}{300} = 1 - \dfrac{{T}_{2}}{500}$

${T}_{2} = \dfrac{5}{3} \times 225 = 375K$

So, temperature of sink is ${T}_{2} = 375 - 273 = 102 ° C$

300calories of heat is given to a heat engine, and it rejects...

Correct answer

Step-by-step solution

More from Thermodynamics