Statement - I : When μ amount of an ideal gas undergoes adiabatic change from state P 1 , V 1 , T 1 to state P 2 , V 2 , T 2 , then work done is W = μ R T 2 - T 1 1 - γ , where γ = C P C V and R = universal gas constant. Statement - II : In the above case, when work is done on the gas, the temperature of the gas would rise.

Step-by-step solution

The work done in an adiabatic process is given by, W adiabatic   = n R T f - T i 1 - γ → statement I is true. For adiabatic process ∆ Q = 0 . From the first law of thermodynamics, ∆ Q = W + Δ U 0 = W + Δ U Δ U = - W If work is done on the gas, i.e. work is negative ∴ Δ U is positive. ∴ The temperature will increase. Hence, statement II is also true.