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JEE Main202228 Jun 2022Morning ShiftPhysicsThermodynamicsActual

The total internal energy of two mole monoatomic ideal gas at temperature T = 300 K will be _____ J . (Given R = 8 . 31 J mol - 1 · K )

Correct answer

0

Step-by-step solution

The internal energy of an ideal gas is a state function and is given by, U = n C v T . For monatomic gas, C v = 3 2 R . Therefore, U = 2 × 3 2 × 8 . 31 × 300 = 7479   J

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