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For a perfect gas, two pressures P 1 and P 2 are shown in figure. The graph shows

Options

  1. AP 1 > P 2
  2. BP 1 < P 2
  3. CP 1 = P 2
  4. DInsufficient data to draw any conclusion

Correct answer

A. P 1 > P 2

Step-by-step solution

We know that the ideal gas equation of gas is P V = n R T Keeping the temperature constant, we have, V ∝ 1 P As seen from graph, V 2 > V 1 , so P 1 > P 2 .

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