A reversible engine has an efficiency of (1)/(4) . If the...

$η = 1 - \dfrac{{T}_{L}}{{T}_{H}}$
$\dfrac{1}{4} = 1 - \dfrac{{T}_{L}}{{T}_{H}}$
$\dfrac{{T}_{L}}{{T}_{H}} = \dfrac{3}{4}$
$2η = \dfrac{1}{2} = 1 - \dfrac{{T}_{L} - 58}{{T}_{H}}$
$\dfrac{{T}_{L} - 58}{{T}_{H}} = \dfrac{1}{2}$
$\dfrac{{T}_{L}}{{T}_{L} - 58} = \dfrac{3 / 4}{1 / 2}$
$2{T}_{L} = 3{T}_{L} - 174$
${T}_{L} = 174K$

This question is bonus as the value given by NTA in option was in degree celsius.