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JEE Main 202127 AugustEvening Shift
Exam
JEE Main
Year
2021
Date
27 August
Shift
Evening Shift
Subject
Physics
Chapter
Thermodynamics

JEE Main 2021 · 27 August · Evening Shift · Physics · Thermodynamics

A heat engine operates between a cold reservoir at temperature T _...

A heat engine operates between a cold reservoir at temperature T2=400K{T}_{2} = 400K and a hot reservoir at temperature T1{T}_{1}. It takes 300J300J of heat from the hot reservoir and delivers 240J240J of heat to the cold reservoir in a cycle. The minimum temperature of the hot reservoir has to be

Correct answer

500

Step-by-step solution

Recall the formula of efficiency of heat engine in terms of work done and heat supplied to the source, η=WQH=1−TLTHη = \dfrac{W}{{Q}_{H}} = 1 - \dfrac{{T}_{L}}{{T}_{H}}, here TL and TH{T}_{L} \text{ and } {T}_{H}, is the temperature of the sink and source⇒60300=1−400TH⇒ \dfrac{60}{300} = 1 - \dfrac{400}{{T}_{H}}⇒TH=500K⇒ {T}_{H} = 500K.

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