An electric appliance supplies 6000 J min - 1 , heat to the system. If the system delivers a power of 90 W . How long it would take to increase the internal energy by 2 . 5 × 10 3 J ?

Step-by-step solution

Recall the formula of the first law of thermodynamics in terms of change in internal energy and work done by the system, Δ U = Q - W , given, Δ U = 2500   J , Q = 6000 60 × t = 100 t     J and W = P × t = 90 t , ⇒ 2500   J = 100 t   J - 90 t   J ⇒ t = 2 . 5 × 10 2   s .