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JEE Main 202126 AugustEvening Shift
Exam
JEE Main
Year
2021
Date
26 August
Shift
Evening Shift
Subject
Physics
Chapter
Thermodynamics

JEE Main 2021 · 26 August · Evening Shift · Physics · Thermodynamics

A refrigerator consumes an average 35W power to operate between...

A refrigerator consumes an average 35W35W power to operate between temperature −10°C- 10 ° C to 25°C25 ° C. If there is no loss of energy then how much average heat per second does it transfer?A refrigerator consumes an average 35W power to operate between temperature - 10 ° C to 25 ° C . If there is no loss of

Options

  1. A350Js−1350J{s}^{- 1}
  2. B298Js−1298J{s}^{- 1}
  3. C263Js−1263J{s}^{- 1}
  4. D35Js−135J{s}^{- 1}

Correct answer

C. 263Js−1263J{s}^{- 1}

Step-by-step solution

A refrigerator consumes an average 35W power to operate between temperature - 10 ° C to 25 ° C . If there is no loss of

W+Q2=Q1W + {Q}_{2} = {Q}_{1}

W=Q1−Q2W = {Q}_{1} - {Q}_{2}

Q2W=Q2Q1−Q2\dfrac{{Q}_{2}}{W} = \dfrac{{Q}_{2}}{{Q}_{1} - {Q}_{2}}

Q2W=T2T1−T2\dfrac{{Q}_{2}}{W} = \dfrac{{T}_{2}}{{T}_{1} - {T}_{2}}

For one second, W=35JW = 35J

Q235=263298−263\dfrac{{Q}_{2}}{35} = \dfrac{263}{298 - 263}

Q2=263J{Q}_{2} = 263J

Hence, average heat per second transferred =263Js−1= 263J{s}^{- 1}

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