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JEE Main 202120 JulyMorning Shift

Exam: JEE Main
Year: 2021
Date: 20 July
Shift: Morning Shift
Subject: Physics
Chapter: Thermodynamics

JEE Main 2021 · 20 July · Morning Shift · Physics · Thermodynamics

The amount of heat needed to raise the temperature of 4moles of a...

The amount of heat needed to raise the temperature of

4moles

of a rigid diatomic gas from

0 ° C

to

50 ° C

when no work is done is

( R

is the universal gas constant)

Options

A $250R$
B $750R$
C $175R$
D $500R$

Correct answer

D. $500R$

Step-by-step solution

\DeltaQ = \DeltaU + \DeltaW

Here

\DeltaW = 0

\DeltaQ = \DeltaU = n{C}_{V}\DeltaT

\DeltaQ = 4 \times \dfrac{5R}{2} ( 50 ) = 500R

Hence option

( 4 ) .

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