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JEE Main 202120 JulyMorning Shift
Exam
JEE Main
Year
2021
Date
20 July
Shift
Morning Shift
Subject
Physics
Chapter
Thermodynamics

JEE Main 2021 · 20 July · Morning Shift · Physics · Thermodynamics

The entropy of any system is given by, S = α ^ 2 [ J β ^ 2 + 3]...

The entropy of any system is given by,
S=α2\betaln[\mukRJβ2+3]S = {\alpha}^{2}\betaln\left[\dfrac{\mukR}{J{\beta}^{2}} + 3\right]
where α\alpha and β\beta are the constants. μ,J,k\mu, J, k and RR are number of moles, mechanical equivalent of heat, Boltzmann's constant and gas constant, respectively.
[TakeS=dQT]\left[\text{Take}S = \dfrac{dQ}{T}\right]
Choose the incorrect option from the following:

Options

  1. Aα\alpha and JJ have the same dimensions.
  2. BS,β,kS, \beta, k and \muR\muR have the same dimensions.
  3. CSS and α\alpha have different dimensions.
  4. Dα\alpha and kk have the same dimensions.

Correct answer

D. α\alpha and kk have the same dimensions.

Step-by-step solution

S = {\alpha}^{2}\betaℓn\left(\dfrac{\mukR}{J{\beta}^{2}} + 3\right)<br/><br />S = \dfrac{Q}{T} = Joule{k}^{- 1}<br/>[α2β]=Joulek−1<br />\left[{\alpha}^{2}\beta\right] = Joule{k}^{- 1}
PV=nRT[\mukRJβ2]=1PV = nRT\left[\dfrac{\mukR}{J{\beta}^{2}}\right] = 1

R=JoulekR = \dfrac{\text{Joule}}{k}
⇒R=Joulek,k=JouleR⇒ R = \dfrac{\text{Joule}}{k}, k = \dfrac{\text{Joule}}{R}
⇒β=(Joulek)⇒ \beta = \left(\dfrac{\text{Joule}}{k}\right)
α2β=(Joulek){\alpha}^{2}\beta = \left(\dfrac{\text{Joule}}{k}\right)
⇒α=⇒ \alpha = dimensionless

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