For the given cyclic process CAB as shown for a gas, the work done...

The work done in a cyclic process is equal to the area of closed P-V curve cycle.

Work done, $W =$ Area of $∆ CAB$

$⇒ W = \dfrac{1}{2} \times AB \times AC$$= \dfrac{1}{2} \times ( 6 - 1 ) \times ( 5 - 1 ) = 10J$

In the given P-V graph, the process is clockwise. So, the work done will be positive which means that the system is doing the work.