In the reaction, The major product formed is

In the reaction, In the reaction, The major product formed is

The major product formed is

Options

A $\mathrm{C}_6 \mathrm{H}_5-\mathrm{CH}_2-\mathrm{CHO}$
B $\mathrm{C}_6 \mathrm{H}_5-\mathrm{COOH}$
C $\mathrm{C}_6 \mathrm{H}_5-$ \mathrm{CH}=\mathrm{CH} $-\mathrm{COOH}$
D $\mathrm{C}_6 \mathrm{H}_5-$ \mathrm{CH}=\mathrm{CH} $-\mathrm{COCH}_3$

Correct answer

C. $\mathrm{C}_6 \mathrm{H}_5-$ \mathrm{CH}=\mathrm{CH} $-\mathrm{COOH}$

Step-by-step solution

The given reaction is an example of Perkin condensation. In this, reaction aromatic aldehydes react with acid anhydride of an aliphatic acid in presence of sodium salt of same acid to form

\alpha, \beta

-unsaturated acid. The steps involved in the process are as follows In the reaction, The major product formed is

Thus, the correct option is (c).

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