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JIPMER 2018
Exam
JIPMER
Year
2018
Subject
Chemistry
Chapter
Chemical Equilibrium

JIPMER 2018 · Chemistry · Chemical Equilibrium

The value of K_ C for the reaction, 2 ~A leftharpoons B+C is 2 ×...

The value of KC\mathrm{K}_{\mathrm{C}} for the reaction, 2 A⇌B+C2 \mathrm{~A} \rightleftharpoons \mathrm{B}+\mathrm{C} is 2×10−32 \times 10^{-3}. At a given time, the composition of reaction mixture is [A]=[B]=[C]=3×10−4M[\mathrm{A}]=[\mathrm{B}]=[\mathrm{C}]=3 \times 10^{-4} \mathrm{M}. In which direction, the reaction will proceed?

Options

  1. AForward direction
  2. BReverse direction
  3. CNo net reaction occur
  4. DNone of these

Correct answer

B. Reverse direction

Step-by-step solution

For the reaction, the reaction quotient QC\mathrm{Q}_{\mathrm{C}} is given by QC=[B][C]/[A]2\mathrm{Q}_{\mathrm{C}}=[\mathrm{B}][\mathrm{C}] /[\mathrm{A}]^2 Given that, [A]=[B]=[C]=3×10−4M[\mathrm{A}]=[\mathrm{B}]=[\mathrm{C}]=3 \times 10^{-4} \mathrm{M} Then, QC=(3×10−4)(3×10−4)(3×10−4)2=1\mathrm{Q}_{\mathrm{C}}=\frac{\left(3 \times 10^{-4}\right)\left(3 \times 10^{-4}\right)}{\left(3 \times 10^{-4}\right)^2}=1 As, QC>KC\mathrm{Q}_{\mathrm{C}}\gt\mathrm{K}_{\mathrm{C}}, so the reaction will proceed in the reverse direction.
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