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AIIMS 2009
Exam
AIIMS
Year
2009
Subject
Chemistry
Chapter
Chemical Bonding and Molecular Structure

AIIMS 2009 · Chemistry · Chemical Bonding and Molecular Structure

The M-O-M bond angles in M_2 O (where M is halogen) is in the order

The M−O−MM-\mathrm{O}-M bond angles in M2O\mathrm{M}_2 \mathrm{O} (where MM is halogen) is in the orderThe M-O-M bond angles in M_2 O (where M is halogen) is in the order

Options

  1. ABr2O>Cl2O>F2O\mathrm{Br}_2 \mathrm{O}>\mathrm{Cl}_2 \mathrm{O}>\mathrm{F}_2 \mathrm{O}
  2. BF2O>Br2O>Cl2O\mathrm{F}_2 \mathrm{O}>\mathrm{Br}_2 \mathrm{O}>\mathrm{Cl}_2 \mathrm{O}
  3. CF2O>Cl2O>Br2O\mathrm{F}_2 \mathrm{O}>\mathrm{Cl}_2 \mathrm{O}>\mathrm{Br}_2 \mathrm{O}
  4. DCl2O>F2O>Br2O\mathrm{Cl}_2 \mathrm{O}>\mathrm{F}_2 \mathrm{O}>\mathrm{Br}_2 \mathrm{O}

Correct answer

A. Br2O>Cl2O>F2O\mathrm{Br}_2 \mathrm{O}>\mathrm{Cl}_2 \mathrm{O}>\mathrm{F}_2 \mathrm{O}

Step-by-step solution

The M-O-M bond angles in M_2 O (where M is halogen) is in the order
In OF2\mathrm{OF}_2 repulsion between lone pairs is greater than that between bond pair since electrons are away from O\mathrm{O} and nearer to F\mathrm{F}. In Cl2O\mathrm{Cl}_2 \mathrm{O}, bonding electrons are nearer to O\mathrm{O} than to Cl\mathrm{Cl}, so the bond angle is greater than 109∘28′109^{\circ} 28^{\prime}. In⁡Br2O\operatorname{In} \mathrm{Br}_2 \mathrm{O}, the bonding electrons are more closer to oxygen than in Cl2O\mathrm{Cl}_2 \mathrm{O}, so the bond angle is largest \left(116^{\circ}\right).
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