Which of the following is correct statement?

- Aluminium is made passive by $\mathrm{HNO}_3$ due to formation of oxide layer. Hence, $\mathrm{HNO}_3$ does not react further but other acids react. $\begin{gathered}2 \mathrm{Al}+6 \mathrm{HCl} \longrightarrow 2 \mathrm{AlCl}_3+3 \mathrm{H}_2 \\ 2 \mathrm{Al}+3 \mathrm{H}_2 \mathrm{SO}_4 \longrightarrow \mathrm{Al}_2\left(\mathrm{SO}_4\right)_3+3 \mathrm{H}_2\end{gathered}$ - NaOH reacts with Al as $2 \mathrm{NaOH}+2 \mathrm{Al} \longrightarrow 2 \mathrm{NaAlO}_2+3 \mathrm{H}_2+2 \mathrm{H}_2 \mathrm{O}$ Thus, NaOH cannot be stored in a vessel made of Al. - Aluminium chloride dissociate in water. - $\mathrm{AlF}_3$ is insoluble in anhydrous HF. Thus, the only correct statement among the given options is (1).