Exam

JIPMER

Year

2017

Subject

Chemistry

Chapter

p Block Elements (Group 15, 16, 17 & 18)

JIPMER 2017 · Chemistry · p Block Elements (Group 15, 16, 17 & 18)

Sulphur reacts with chlorine in 1: 2 ratio and forms X . Hydrolysis...

Sulphur reacts with chlorine in $1: 2$ ratio and forms $X$. Hydrolysis of $X$ gives a sulphur compound $Y$. The hydridisation of central atom in the anion $Y$ is

Step-by-step solution

When sulphur reacts with chlorine in $1: 2$ ratio the $\mathrm{SCl}_4$ is obtained which on hydrolysis gives $\mathrm{H}_2 \mathrm{SO}_4$. Hence, the compound ' $X$ ' is $\mathrm{SCl}_4$ and ' $Y$ ' is $\mathrm{H}_2 \mathrm{SO}_4$ $\mathrm{SCl}_4+4 \mathrm{H}_2 \mathrm{O} \longrightarrow \underset{\text{ Unstable }}{\mathrm{S}(\mathrm{OH})_4}+4 \mathrm{HCl} \mathrm{S}(\mathrm{OH})_4 \longrightarrow \underset{\substack{\text{ Sulphurous acid }}}{\mathrm{H}_2 \mathrm{SO}_4}+\mathrm{H}_2 \mathrm{O}$ The hybridisation of sulphur in $\mathrm{SO}_3^{2-}$ is $s p^3$.