Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JIPMER2018PhysicsMechanical Properties of Solids

If compressibility of material is 4 10⁻⁵ per atm, pressure is 100 atm and volume is 100 ~cm ^3 , then find V = ?

Options

  1. A0.4 ~cm ^3
  2. B0.8 ~cm ^3
  3. C0.6 ~cm ^3
  4. D0.2 ~cm ^3

Correct answer

A. 0.4 ~cm ^3

Step-by-step solution

Compressibility | |= 1 Bulk modulus of elasticits | |= pV V or = l ( pV V ) = V pV aligned V = ( p . V ) & =4 10⁻⁵ (100 100 10⁻⁶ ) & =0.4 10⁻⁶ ~m ^3=0.4 ~cm ^3 aligned

Practice Mechanical Properties of Solids on Quantrex Academy →

More from Mechanical Properties of Solids

Match List I with List II : List I List II A. Young's Modulus I. d L ( L d ) B. Compressibility II. F L A( L) C. Bulk Modulus III. - 1 P ( V V ) D. Poisson's Ratio IV. -P ( V V ) C 2026A metallic bar of Young's modulus, 0.5 10¹¹ ~N ~m ⁻² and coefficient of linear thermal expansion 10⁻⁵ ^ C ⁻¹ , length 1 m and area of cross-section 10⁻³ ~m ^2 is heated from 0^ C t 2024The maximum elongation of a steel wire of 1 m length if the elastic limit of steel and its Young's modulus, respectively, are 8 10^8 ~N ~m ⁻² and 2 10¹¹ ~N ~m ⁻² , is: 2024Let a wire be suspended from the ceiling (rigid support) and stretched by a weight W attached at its free end. The longitudinal stress at any point of cross-sectional area A   2023The amount of elastic potential energy per unit volume (in SI unit) of a steel wire of length 100 ~cm to stretch it by 1 ~mm is (if Young's modulus of the wire =2.0 10¹¹ ~N ~m ⁻² ) 2023Given below are two statements : One is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A): The stretching of a spring is determined by the shear modu 2022A wire of length L , area of cross section A is hanging from a fixed support. The length of the wire changes to L 1 when mass M is suspended from its free end. The expression for Y 2020Identify the incorrect statement. 2019 Full Mechanical Properties of Solids list All JIPMER PYQs