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JIPMER 2018
Exam
JIPMER
Year
2018
Subject
Physics
Chapter
Motion in One Dimension

JIPMER 2018 · Physics · Motion in One Dimension

A runner starts from O and goes to O following path OQRO in lhr....

A runner starts from O and goes to O following path OQRO in lhr. What is net displacement and average speed? A runner starts from O and goes to O following path OQRO in lhr. What is net displacement and average speed?

Options

  1. A0,3.57 km/hr0,3.57 \mathrm{~km} / \mathrm{hr}
  2. B0,0 km/hr0,0 \mathrm{~km} / \mathrm{hr}
  3. C0,2.570,2.57 km/hr
  4. D0,1 km/hr0,1 \mathrm{~km} / \mathrm{hr}

Correct answer

A. 0,3.57 km/hr0,3.57 \mathrm{~km} / \mathrm{hr}

Step-by-step solution

∵\because Runner starts from O and goes to O . So, net displacement is zero. ∵ Average speed = Total distance  Total time =OQ+QR+RO total time \begin{aligned} \because \text{ Average speed } & =\frac{\text{ Total distance }}{\text{ Total time }} \\ & =\frac{\mathrm{OQ}+\mathrm{QR}+\mathrm{RO}}{\text{ total time }}\end{aligned}1km+(2πr)(14)+1km1hr=2+π2=3.57km/hr\begin{aligned} & \frac{1 \mathrm{ km}+(2 \pi \mathrm{r})\left(\frac{1}{4}\right)+1 \mathrm{ km}}{1 \mathrm{hr}} \\ = & 2+\frac{\pi}{2}=3.57 \mathrm{ km} / \mathrm{hr}\end{aligned}$
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