JIPMER2018PhysicsMotion in One Dimension
A ball is thrown upwards with a speed u from a height h above the ground. The time taken by the ball to hit the ground is
Options
- A2 h / g
- B8 h / g
- Cu^2+2 g h g
- Du g + 2 h g
Correct answer
C. u^2+2 g h g
Step-by-step solution
Time taken to reach the highest point from the height h is obtained from equation, v = u - gt 0= u - gt or t = u g Height attained above h is obtained from v ^2- u ^2=2(- g ) h ₁ or 0- u ^2=2(- g ) h ₁ or h ₁= u ^2 2 ~g Total height, h ₂= [ h ₁+ h = u ^2 2 ~g + h ] Time taken to hit the ground is obtained from, aligned h ₂ & = ut + 1 2 at ^2 u ^2 2 ~g + h & =0+ 1 2 gt ^2 aligned Total time taken, t = ( u ^2+2 ~g ~h ) g ^2