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JIPMER 2009
Exam
JIPMER
Year
2009
Subject
Physics
Chapter
Motion in One Dimension

JIPMER 2009 · Physics · Motion in One Dimension

A car moves from X to Y with a uniform speed v_u and returns to Y...

A car moves from XX to YY with a uniform speed vuv_u and returns to YY with a uniform speed vdv_d. The average speed for this round trip is

Options

  1. A2vdvuvd+vu\frac{2 v_d v_u}{v_d+v_u}
  2. Bvuvd\sqrt{v_u v_d}
  3. Cvdvuvd+vu\frac{v_d v_u}{v_d+v_u}
  4. Dvu+vd2\frac{v_u+v_d}{2}

Correct answer

A. 2vdvuvd+vu\frac{2 v_d v_u}{v_d+v_u}

Step-by-step solution

Let t1andt_1 andt_2betimestakenbythecartogofrombe times taken by the car to go fromXtotoYandthenfromand then fromYtotoXrespectively.Then,respectively. Then,t_1+t_2=\frac{X Y}{v_u}+\frac{X Y}{v_d}=X Y(vu+vdvuvd)Y\left(\frac{v_u+v_d}{v_u v_d}\right) Total distance travelled =XY+XY=2XY=X Y+X Y=2 X Y Therefore, average speed of the car for this round trip is vav=2XYXY(vu+vdvuvd) or vav=2vuvdvu+vd\begin{aligned} v_{\mathrm{av}} & =\frac{2 X Y}{X Y\left(\frac{v_u+v_d}{v_u v_d}\right)} \\ \text{ or } \quad v_{\mathrm{av}} & =\frac{2 v_u v_d}{v_u+v_d}\end{aligned}
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