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NEET 2009
Exam
NEET
Year
2009
Subject
Physics
Chapter
Motion in One Dimension

NEET 2009 · Physics · Motion in One Dimension

A bus is moving with a speed of 10 ~ms^ -1 on a straight road. A...

A bus is moving with a speed of 10 ms−110 \mathrm{~ms}^{-1} on a straight road. A scooterist wishes to overtake the bus in 100 s100 \mathrm{~s}. If the bus is at a distance of 1 km1 \mathrm{~km} from the scooterist, with what speed should the scooterist chase the bus?A bus is moving with a speed of 10 ~ms^ -1 on a straight road. A scooterist wishes to overtake the bus in 100 ~s . IfA bus is moving with a speed of 10 ~ms^ -1 on a straight road. A scooterist wishes to overtake the bus in 100 ~s . If

Options

  1. A20 ms−120 \mathrm{~ms}^{-1}
  2. B40 ms−140 \mathrm{~ms}^{-1}
  3. C25 ms−125 \mathrm{~ms}^{-1}
  4. D10 ms−110 \mathrm{~ms}^{-1}

Correct answer

A. 20 ms−120 \mathrm{~ms}^{-1}

Step-by-step solution

Let yy be the relative velocity of scooter(s) w.r.t. bus (B)(B), then A bus is moving with a speed of 10 ~ms^ -1 on a straight road. A scooterist wishes to overtake the bus in 100 ~s . If
∴\quadvS=v+vB Relative velocity = displacement / time =1000100=10 ms−1\begin{aligned} \therefore \quadv_S & =\mathrm{v}+\mathrm{v}_{\mathrm{B}}\\ \text{ Relative velocity }& =\text{ displacement }/ \text{ time }\\ & =\frac{1000}{100}=10 \mathrm{~ms}^{-1} \end{aligned}Now, substituting the value of in Eq. (i), we get vS=\mathrm{v}_{\mathrm{S}}=10+10=20  ms−1\mathrm{~ms}^{-1}
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