Two boys are standing at the ends A and B of a ground, where A B=a . The boy at B starts running in a direction perpendicular to A B with velocity v₁ . The boy at A starts running simultaneously with velocity v and catches the other boy in

Question

Two boys are standing at the ends A and B of a ground, where A B=a . The boy at B starts running in a direction perpendicular to A B with velocity v₁ . The boy at A starts running simultaneously with velocity v and catches the other boy in a time t , where t is

Quantrex Academy · Accepted Answer

Correct answer: B. a^2 v^2-v₁^2

Distance covered by boy A in time tA C=v t...(i) Distance covered by boy B in time tB C=v₁ t...(ii) Using Pythagorus theorem aligned & & A C^2 & =A B^2+B C^2 & or & (v t)^2 & =a^2+ (v₁ t )^2 & or & v^2 t^2-v₁^2 t^2 & =a^2 & or & t^2 (v^2-v₁^2 ) & =a^2 aligned = a^2 (v^2-v₁^2 )

Two boys are standing at the ends A and B of a ground, where A B=a . The boy at B starts running in a direction perpendicular to A B with velocity v₁ . The boy at A starts running simultaneously with velocity v and catches the other boy in a time t , where t is

Options

Correct answer

Step-by-step solution

More from Motion in One Dimension