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JIPMER2007PhysicsOscillations

A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 ~cm / s . The frequency of its oscillation is

Options

  1. A3 Hz
  2. B2 Hz
  3. C4 Hz
  4. D1 Hz

Correct answer

D. 1 Hz

Step-by-step solution

Maximum speed of a particle executing SHM is u_ =a =a(2 n) n= u_ 2 a Here, u_ =31.4 ~cm / s , a=5 ~cm Substituting the given values, we have n= 31.4 2 3.14 5 =1 ~Hz

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