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NEET2007PhysicsOscillationsActual

The particle executing simple harmonic motion has a kinetic energy K₀ ^2 t . The maximum values of the potential energy and the total energy are respectively.

Options

  1. AK₀ / 2 and K₀
  2. BK₀ and 2 K₀
  3. CK₀ and K₀
  4. D0 and 2 K₀ .

Correct answer

C. K₀ and K₀

Step-by-step solution

K . E. =K₀ ^2 t Maximum P. E. = Maximum K. E. = Total energy = K ₀

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