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NEET 2007
Exam
NEET
Year
2007
Subject
Physics
Chapter
Oscillations

NEET 2007 · Physics · Oscillations

The particle executing simple harmonic motion has a kinetic energy...

The particle executing simple harmonic motion has a kinetic energy K0cos⁡2K_0 \cos ^2 ωt\omega t. The maximum values of the potential energy and the total energy are respectively.

Options

  1. AK0/2K_0 / 2 and K0K_0
  2. BK0K_0 and 2K02 K_0
  3. CK0K_0 and K0K_0
  4. D0 and 2K02 K_0.

Correct answer

C. K0K_0 and K0K_0

Step-by-step solution

∵K\because \mathrm{K}. E. =K0cos⁡2ωt=K_0 \cos ^2 \omega t ∴\therefore Maximum P. E. = Maximum K. E. = Total energy =K0=\mathrm{K}_0
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