Maximum acceleration in SHM

Acceleration of a particle in S.H.M is given by $a=-\omega^2 X$ Where, x is the displacement from mean position Acceleration will be maximum, When $\mathrm{x}=\mathrm{A}$, where A is amplitude $$\begin{aligned} \therefore \quad & \mathrm{a}_{\max }=-\omega^2 \mathrm{~A} \\ & \left|\mathrm{a}_{\max }\right|=\omega^2 \mathrm{~A} \end{aligned}$$