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JIPMER 2005
Exam
JIPMER
Year
2005
Subject
Physics
Chapter
Oscillations

JIPMER 2005 · Physics · Oscillations

A simple pendulum of length l has a maximum angular displacement θ...

A simple pendulum of length ll has a maximum angular displacement θ\theta. The maximum kinetic energy of the bob isA simple pendulum of length l has a maximum angular displacement θ . The maximum kinetic energy of the bob is

Options

  1. Amgl(1−cos⁡θ)m g l(1-\cos \theta)
  2. B0.5 mgl
  3. Cmgl
  4. D0.5 mgl

Correct answer

A. mgl(1−cos⁡θ)m g l(1-\cos \theta)

Step-by-step solution

Here : length of pendulum =l=l A simple pendulum of length l has a maximum angular displacement θ . The maximum kinetic energy of the bob is maximum angular displacement =θ=\theta mass of the bob =m=m Now height of the bob at maximum angular displacement is h=l−lcos⁡θ=l(1−cos⁡θ)h=l-l \cos \theta=l(1-\cos \theta) Also at the end of the displacement kinetic energy of the bob = potential energy of the bob =mgh=mgl(1−cos⁡θ)=m g h=m g l(1-\cos \theta)
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