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NEET 2005
Exam
NEET
Year
2005
Subject
Physics
Chapter
Oscillations

NEET 2005 · Physics · Oscillations

A particle executing simple harmonic motion of amplitude 5 ~cm has...

A particle executing simple harmonic motion of amplitude 5 cm5 \mathrm{~cm} has maximum speed of 31.4 cm/s31.4 \mathrm{~cm} / \mathrm{s}. The frequency of its oscillation is:

Options

  1. A4 Hz4 \mathrm{~Hz}
  2. B3 Hz3 \mathrm{~Hz}
  3. C2 Hz2 \mathrm{~Hz}
  4. D1 Hz1 \mathrm{~Hz}

Correct answer

D. 1 Hz1 \mathrm{~Hz}

Step-by-step solution

Here a=5 cm,Vmax⁡=31.4 cm sa=5 \mathrm{~cm}, V_{\max }=\frac{31.4 \mathrm{~cm}}{\mathrm{~s}}Vmax⁡=ωa=31.4=2πv×5⇒31.4=10×3.14×V⇒V=1Hz\begin{aligned} & V_{\max }=\omega a=31.4=2 \pi \mathrm{v} \times 5 \\ & \Rightarrow 31.4=10 \times 3.14 \times V \\ & \Rightarrow \quad V=1 Hz \end{aligned}$$
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