Two simple pendulums of length 0.5 m and 20 m respectively are given small linear displacement in one direction at the same time. They will again be in the phase when the pendulum of shorter length has completed x

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Correct answer: C. 2

Time period of simple pendulum For Ist pendulum aligned T_1 & =2 π (5)/(g) & =2 π (5)/(9.8) = 20 ~s aligned For IInd pendulum T_2=2 π (20)/(g) =2 π (20)/(9.8) =2 20 ~s Suppose the time will be in same phase is t then aligned (1)/(t) & =(1)/(T_1)-(1)/(T_2) & = 1 20 - 1 2 20 aligned = 1 2 20 So, t=2 20 Hence, the number of oscillation of simple pendulum of shorter length (x)= 2 20 20 =2 .

Two simple pendulums of length 0.5 m and 20 m respectively are...

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