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JIPMER 2019
Exam
JIPMER
Year
2019
Subject
Physics
Chapter
Rotational Motion

JIPMER 2019 · Physics · Rotational Motion

Two disc having mass ratio 1 / 2 and diameter ratio 2 / 1 then find...

Two disc having mass ratio 1/21 / 2 and diameter ratio 2/12 / 1 then find ratio of moment of inertia.

Options

  1. A2:12: 1
  2. B1:11: 1
  3. C1:21: 2
  4. D2:32: 3

Correct answer

A. 2:12: 1

Step-by-step solution

Given, mass ratio of two disc m1:m2=1:2 i.e. m1m2=12\mathrm{m}_1: \mathrm{m}_2=1: 2 \text{ i.e. } \frac{\mathrm{m}_1}{\mathrm{ m}_2}=\frac{1}{2} and diameter ratio d1d2=21⇒r1r2=21∴\frac{\mathrm{d}_1}{\mathrm{ d}_2}=\frac{2}{1} \Rightarrow \frac{\mathrm{r}_1}{\mathrm{r}_2}=\frac{2}{1} \therefore Ratio of their moment of inertia, I1I2=m1r122m2r222=m1m2⋅(r1r2)2=12(21)2=21∴I1:I2=2:1\begin{array}{ll} \quad \frac{\mathrm{I}_1}{\mathrm{I}_2}=& \frac{\frac{\mathrm{m}_1 \mathrm{r}_1^2}{2}}{\frac{\mathrm{m}_2 \mathrm{r}_2^2}{2}}=\frac{\mathrm{m}_1}{\mathrm{ m}_2} \cdot\left(\frac{\mathrm{r}_1}{\mathrm{r}_2}\right)^2=\frac{1}{2}\left(\frac{2}{1}\right)^2=\frac{2}{1} \\ \therefore \quad \mathrm{I}_1: \mathrm{I}_2=2: 1 \end{array}
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