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AIIMS 2001
Exam
AIIMS
Year
2001
Subject
Chemistry
Chapter
Chemical Bonding and Molecular Structure

AIIMS 2001 · Chemistry · Chemical Bonding and Molecular Structure

Smallest intermolecular distance is found in

Smallest intermolecular distance is found in

Options

  1. AO2\mathrm{O}_2
  2. BO2+\mathrm{O}_2^{+}
  3. CO2−\mathrm{O}_2^{-}
  4. DO22−\mathrm{O}_2^{2-}

Correct answer

B. O2+\mathrm{O}_2^{+}

Step-by-step solution

In O2\mathrm{O}_2, the bond order =2=2 In O2+\mathrm{O}_2^{+}, the bond order =2.5=2.5 In O2−\mathrm{O}_2^{-}, the bond order =1.5=1.5 In O2−2\mathrm{O}_2^{-2}, the bond order =1=1 As the bond order in O2+\mathrm{O}_2^{+}is highest, so its internuclear distance is smallest.
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