A chemical reaction has a rate constant of 6.93 10⁻³ ~s ⁻¹ . How much time will it take for the reaction to be 93.75 % complete? (Given : 2 = 0.301 )

Step-by-step solution

The unit of the rate constant is s ⁻¹ , indicating a first-order reaction. The half-life of the reaction is given by: t_ 1/2 = 0.693 k = 0.693 6.93 10⁻³ = 100 ~s For 93.75 % completion, the percentage of reactant remaining is: 100 % - 93.75 % = 6.25 % The fraction of reactant remaining is: 6.25 100 = 1 16 = ( 1 2 )^4 This indicates that 4 half-lives have passed. Total time required = 4 t_ 1/2 = 4 100 ~s = 400 ~s Answer: 400 ~s