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NEET 2026
Exam
NEET
Year
2026
Subject
Chemistry
Chapter
Chapter

NEET 2026 · Chemistry · Chapter

The stability of the lower oxidation state increases down a group...

The stability of the lower oxidation state increases down a group in the p-block due to the inert pair effect. Based on this principle, which of the following oxides will act as the most powerful oxidizing agent?

Options

  1. ACO2CO_{2}
  2. BSiO2SiO_{2}
  3. CSnO2SnO_{2}
  4. DPbO2PbO_{2}

Correct answer

D. PbO2PbO_{2}

Step-by-step solution

The elements given belong to Group 14 of the periodic table: C, Si, Sn, Pb.

The general oxidation states exhibited by Group 14 elements are +2 and +4. Down the group, the stability of the lower oxidation state (+2) increases and that of the higher oxidation state (+4) decreases due to the inert pair effect.

For lead (Pb), the +2 oxidation state is much more stable than the +4 oxidation state. In PbO2PbO_{2}, lead is in the +4 oxidation state, which is highly unstable. Therefore, PbO2PbO_{2} readily accepts electrons to get reduced to the more stable Pb2+Pb^{2+} state (PbOPbO).

Since it easily undergoes reduction, PbO2PbO_{2} acts as a very powerful oxidizing agent compared to CO2CO_{2}, SiO2SiO_{2}, and SnO2SnO_{2}, where the +4 oxidation state is relatively stable.

Answer: PbO2PbO_{2}
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