Identify the correct count of σ -bonds, π -bonds, and lone pairs of...

The chemical formula of aniline is $C_6H_5NH_2$.

The structure consists of a benzene ring attached to an amino group ($-NH_2$).

Number of $\sigma$-bonds:
C-C bonds in the benzene ring = $6$
C-H bonds in the benzene ring = $5$
C-N bond = $1$
N-H bonds = $2$
Total $\sigma$-bonds = $6 + 5 + 1 + 2 = 14$

Number of $\pi$-bonds:
C=C double bonds in the benzene ring = $3$
Total $\pi$-bonds = $3$

Number of lone pairs:
Nitrogen has $5$ valence electrons. It shares $3$ electrons in bonding ($1$ with carbon, $2$ with hydrogen), leaving $2$ non-bonding electrons.
Total lone pairs = $1$

Thus, the count of $\sigma$-bonds, $\pi$-bonds, and lone pairs is $14$, $3$, and $1$ respectively.

Answer: $14,\ 3,\ 1$