The reaction, CF_3CH_2OH + CH_3CH_2ONa arrow CF_3CH_2ONa +...

The given reaction is an acid-base reaction where $\mathrm{CF_3CH_2OH}$ acts as an acid and $\mathrm{CH_3CH_2ONa}$ acts as a base.

The reaction proceeds in the forward direction, which implies that a stronger acid and a stronger base react to form a weaker acid and a weaker base.

Here, $\mathrm{CF_3CH_2OH}$ donates a proton to the ethoxide ion ($\mathrm{CH_3CH_2O^-}$) to form ethanol ($\mathrm{CH_3CH_2OH}$).

This indicates that $\mathrm{CF_3CH_2OH}$ (2,2,2-trifluoroethanol) is a stronger acid than $\mathrm{CH_3CH_2OH}$ (ethanol).

The strong $-I$ effect of the three fluorine atoms stabilizes the $\mathrm{CF_3CH_2O^-}$ ion, making it a weaker base than the ethoxide ion, and consequently making 2,2,2-trifluoroethanol a stronger acid than ethanol.

Answer: 2,2,2-trifluoroethanol is a stronger acid than ethanol